3x^2+2x-275=0

Solution for 3x^2+2x-275=0 equation:

3x^2+2x-275=0

a = 3; b = 2; c = -275;
Δ = b2-4ac
Δ = 22-4·3·(-275)
Δ = 3304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3304}=\sqrt{4*826}=\sqrt{4}*\sqrt{826}=2\sqrt{826}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{826}}{2*3}=\frac{-2-2\sqrt{826}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{826}}{2*3}=\frac{-2+2\sqrt{826}}{6}
$